Quote:
Originally Posted by Danr55
Bernie, Try with ABC being a straight line. A being moved out of line 1/8" creating lines AC and BC. The issue is to solve for the distance from point B to line AC as the short leg of a triangle.
Line ABC=120"
Line AB = 26"
Line BC = 94"
Point A moves in an arc with Point C at the center, .125"
Solve for the distance from B to line AC.
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Dang Dan, give 'em a hint. Tell them that the shortest distance from point B to line AC will be a line that is perpendicular to AC. Now you've got a right triangle with this newly created line being the side you're trying to solve. AB is the hypotenuse. Now that's a pretty good hint.
