01-13-2014, 12:23 PM
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Half-Ass Member
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Join Date: Jun 2005
Cobra Make, Engine: ERA #732, 428FE (447 CID), TKO600, Solid Flat Tappet Cam, Tons of Aluminum
Posts: 22,025
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Quote:
Originally Posted by Danr55
Bernie, Try with ABC being a straight line. A being moved out of line 1/8" creating lines AC and BC. The issue is to solve for the distance from point B to line AC as the short leg of a triangle.
Line ABC=120"
Line AB = 26"
Line BC = 94"
Point A moves in an arc with Point C at the center, .125"
Solve for the distance from B to line AC.
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Dang Dan, give 'em a hint. Tell them that the shortest distance from point B to line AC will be a line that is perpendicular to AC. Now you've got a right triangle with this newly created line being the side you're trying to solve. AB is the hypotenuse. Now that's a pretty good hint.  |
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